5x^2-11=4x^2+5

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Solution for 5x^2-11=4x^2+5 equation:



5x^2-11=4x^2+5
We move all terms to the left:
5x^2-11-(4x^2+5)=0
We get rid of parentheses
5x^2-4x^2-5-11=0
We add all the numbers together, and all the variables
x^2-16=0
a = 1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·1·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*1}=\frac{-8}{2} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*1}=\frac{8}{2} =4 $

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